DIFFERENSIAL 3 BARANG
SOAL :
Diketahui :
C = 0,050Qa2 + Qb2 + 0,75Qc2 + 2QaQb + 3QbQc + QaQc +9187,50
Persamaan fungsi permintaan :
Pa = 325 – 4Qa
Pb = 560 – 5Qb
Pc = 355 – 3Qc
Diminta :
a. Jumlah factor produksi masing-masing barang
b. Harga Per unit masing-masing barang
c. Besarnya laba maksimum tersebut
Jawab :
Cara I :
R = P(Q)
Ra= Pa(Qa)
Ra= 325 – 4Qa (Qa) ® -4Qa2 + 325Qa
Rb= 560 – 5Qb (Qb) ® -5Qb2 + 560Qb
Rc= 355 – 3Qc (Qc) ® -3Qc2 + 355Qc
= -4Qa2 + 325Qa - 5Qb2 + 560Qb – 3Qc2 + 355Qc – (0,050Qa2 + Qb2 + 0,75Qc2 + 2QaQb + 3QbQc + QaQc +9187,50)
= -4Qa2 + 325Qa - 5Qb2 + 560Qb – 3Qc2 + 355Qc – 0,050Qa2 - Qb2 - 0,75Qc2 - 2QaQb - 3QbQc - QaQc - 9187,50
= -4,5Qa2 + 325Qa - 6Qb2 + 560Qb – 3,75Qc2 + 355Qc - 2QaQb - 3QaQc - QaQc - 9187,50
Jadi
p a = -4,5Qa2 + 325Qa - 2QaQb – QaQc
pa1 = -9Qa + 325 – 2Qb – Qc ® -9Qa – 2Qb – Qc = -325 ( Persamaan I)
pb = - 6Qb2 + 560Qb - 2QaQb - 3QbQc
pb1= -12Qb + 560 – 2Qa – 3Qc ® -2Qa – 12Qb – 3Qc = -560 (Persamaan II)
pc = -3,75Qc2 + 355Qc - 3QbQc - QaQc
pc1= -7,5Qc + 355 – 3Qb – Qa ® – Qa – 3Qb - 7,5Qc = -355 (Persamaan III)
Eliminasi Persamaan I & II :
-9Qa – 2Qb – Qc = -325 x 6 ® -54Qa2 – 12Qb- 6Qc = -1.950
2Qa – 12Qb – 3Qc = -560 x 1 ® -2Qa2 -12Qb – 3Qc = -560
-52Qa2 -3Qc = -1.390 (Persamaan IV)
2Qa – 12Qb – 3Qc = -560 x 1 ® -2Qa2 – 12Qb- 3Qc = -560
– Qa – 3Qb - 7,5Qc = -355 x 4 ® -4Qa2 - 12Qb – 30Qc = -1.420
2Qa2 - 27Qc = 860 (Persamaan V)
Eliminasi persamaan IV & V :
-52Qa - 3Qc = -1.390 x 9 ® -468Qa – 27Qb - 3Qc = -12.510
2Qa - 27Qc = 860 x 1 ® 2Qa + 27Qb = 860
-466Qa = -11.650
Qa = 25
2Qa2 - 27Qc = 860 – Qa – 3Qb - 7,5Qc = -355
27Qc = 860 – 50 -3Qb = -355 + 25 + 225
Qc = 30 Qb = 35
a) Jumlah produksi
Qa = 25
Qb = 35
Qc = 30
b) Harga jual atau unit
Pa = 325 – 4(Qa) Pb = 560 – 5(Qb) Pc = 355 – 3(Qc)
Pa = 325 – 4(25) Pb = 560 – 5(35) Pc = 355 – 3(30)
Pa =325 – 100 Pb = 560 - 175 Pc = 355 - 90
Pa = 225 Pb = 385 Pc = 265
c) Laba
Qa = 25
Qb = 35
Qc = 30
p = -4,5Qa2 + 325Qa - 6Qb2 + 560Qb – 3,75Qc2 + 355Qc - 2QaQb - 3QaQc - QaQc – 9187,50
p = -2.812,5 = 8.125 – 7.350 + 19.600 + 3.375 + 10.650 -1.750 – 3.150 – 750 – 9.187,50
p = 10.000
Cara II :
Ra= -4Qa2 + 325Qa
Rb= -5Qb2 + 560Qb
Rc= -3Qc2 + 355Qc
Ra’ = Mra
Mra = -8Qa + 325
Mrb = -10Qb + 560
Mrc = -6Qc + 355
C = 0,050Qa2 + Qb2 + 0,75Qc2 + 2QaQb + 3QbQc + QaQc +9187,50
C’= Mc
Mca= Qa + 2qb +Qc ® Mca = Qa + 2Qb + Qc
Mcb= 2Qb + 2Qa + 3Qc ® Mcb = 2Qa + 2Qb + 3Qc
Mcc= 1,5Qc + 3Qb + Qa ® Mcc = Qa + 3Qb + 1,5Qc
pmaks a ® Mra = Mca
-8Qa + 325 = Qa + 2Qb + Qc
325 = Qa + 8Qa + 2Qb + Qc
325 = 9Qa + 2Qb + Qc (Persamaan I)
pmaks b ® Mrb = Mcb
-10Qb + 560 = 2Qa + 2Qb + 3Qc
560 = 2Qa + 2Qb + 10Qb + 3Qc
560 = 2Qa + 12Qb + 3Qc (Persamaan II)
pmaks c ® Mrc = Mcc
-6Qc + 355 = Qa + 3Qb + 1,5Qc
355 = Qa + 3Qb + 1,5Qc + 6Qc
355 = Qa + 3Qb + 7,5Qc (Persamaan III)
Eliminasi pers I&II
325 = 9Qa + 2Qb + Qc x3 ® 975 = 27Qa + 6Qb + 3Qc
560= 2Qa + 12Qb + 3Qc x1 ® 560 = 2Qa + 12Qb + 3Qc
415 = 25Qa – 6Qb (Persamaan IV)
Eliminasi pers II&III
560 = 2Qa + 12Qb + 3Qc x5 ® 2800 = 10Qa+60Qb+15Qc
355 = Qa + 3Qb + 7,5Qc x2 ® 710 = 2Qa+6Qb+15Qc
2090 = 8Qa=54Qb (Persamaan V)
Eliminasi pers IV& V
415 = 25Qa – 6Qb x9 ® 3735 = 225Qa - 54Qb
2090 = 8Qa=54Qb x1 ® 710 = 2Qa+6Qb+15Qc
5825 = 233Qa
25 = Qa
415 = 25Qa – 6Qb 560 = 2Qa + 12Qb + 3Qc
415 = 25 (25) – 6Qb 560 = 2(25) + 12(35) + 3Qc
415 – 625 = -6Qb 560-50-420 = 3Qc
35 = Qb 30 = Qc
a) Jumlah produksi
Qa = 25
Qb = 35
Qc = 30
b) Harga jual atau unit
Pa = 325 – 4(Qa) Pb = 560 – 5(Qb) Pc = 355 – 3(Qc)
Pa = 325 – 4(25) Pb = 560 – 5(35) Pc = 355 – 3(30)
Pa =325 – 100 Pb = 560 - 175 Pc = 355 - 90
Pa = 225 Pb = 385 Pc = 265
c) Laba
Qa = 25
Qb = 35
Qc = 30
p = -4,5Qa2 + 325Qa - 6Qb2 + 560Qb – 3,75Qc2 + 355Qc - 2QaQb - 3QaQc - QaQc – 9187,50
p = -2.812,5 = 8.125 – 7.350 + 19.600 + 3.375 + 10.650 -1.750 – 3.150 – 750 – 9.187,50
p = 10.000
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